First slide

Rectilinear Motion

Question

A car starts from rest and moves with uniform acceleration ‘a’. Then the distance covered by the car in 5^th sec is

Easy

A

1.5a
B

2.5a
C

3.5a
D

4.5a

Solution

Given that $u = 0$
$n = 5$
$∴$ The distance travelled in nth sec is
$\begin{array}{l} S_{n} = u + a (n - \frac{1}{2}) \\ = 0 + a (5 - \frac{1}{2}) \\ = \frac{9}{2} a \\ = 4.5 a \end{array}$

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