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Q.

A car is travelling on a road. The maximum velocity the car can attain is 24 ms-1 and the maximum deceleration is 4 ms-2. If car starts from rest and comes to rest after travelling 1032 m in the shortest time of 56 s, the maximum acceleration that the car can attain is

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a

6 ms-2

b

1.2 ms-2

c

12 ms-2

d

3.6 ms-2

answer is B.

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Detailed Solution

Area of v-t graph =displacement∴ 1032=1256+t0×24or t0=30 sDeceleration time t1=244=6 s∴ Acceleration time t2=56-t0-t1=20 s∴ Acceleration =2420=1.2 m/s2
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