First slide

Different question variety formed

Question

A car travelling at a speed of 30 km/hr is brought to a halt in 8 m by applying brakes. If the same car is travelling at 60 km/hr it can be brought to a halt with the same braking force in:

Moderate

A

8m
B

16m
C

24m
D

32m

Solution

Stopping distance is proportional to square of the vehicle's speed $(s = \frac{u^{2}}{2 a})$ .
Hence for same car moving at different speed $s' = s {(\frac{u'}{u})}^{2} = 8 \times {(\frac{60}{30})}^{2} m = 32 m$ .

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