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Q.

A car is travelling on a straight road. The maximum velocity the car can attain is 24 ms-1. The maximum acceleration and deceleration it can attain are 1 ms-2 and 4 ms-2 respectively. The shortest time the car takes from rest to rest in a distance of 200 m is,

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a

22.4 s

b

30 s

c

11.2 s

d

5.6 s

answer is A.

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Detailed Solution

Deceleration is four times. Therefore, deceleration time should be 14th.vmax=a1(4t)=(1)(4t)=4tArea of v-t graph = displacement∴ 200=12(5t)(4t)or t=20 sTotal journey time =5t=22.4 s
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