A car turns a corner on a slippery road at a constant speed of 12 m/s. If the coefficient of friction is 0.4, the minimum radius of the arc in metre in which the car turns is
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a
72
b
36
c
18
d
9
answer is B.
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Detailed Solution
Friction = µ (m g)Centripetal force = m v2 / r∴ μmg=mv2/r or r=v2/μgor r=12×12(0.4×10)=36m.