First slide

Force

Question

A car turns a corner on a slippery road at a constant speed of 12 m/s. If the coefficient of friction is 0.4, the minimum radius of the arc in metre in which the car turns is

Easy

A

72
B

36
C

18
D

9

Solution

Friction = µ (m g)
Centripetal force = m v² / r
$∴ μmg = {mv}^{2} / r or r = (v^{2} / μg)$
or $r = \frac{12 \times 12}{(0 .4 \times 10)} = 36 m$ .

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