Questions
A carnot engine has an efficiency of 40%. Keeping the source temperature unchanged, what should be the percentage change in the temperature of the sink in order to increase the efficiency by 10%?
detailed solution
Correct option is C
1−T2T1=η⇒T2=T1(1−η)Initially, T2=T1(1−0.4)=0.6 T1Finally, T21=T1[1−(0.4+10100×0.4)]=0.56 T 1∴ T2−T21T2=0.6T1−0.56T10.6T=6.66%So temperature of the sink should be decreased by 6.66%Talk to our academic expert!
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