A Carnot engine having an efficiency of 110 is being used as a refrigerator. If the work done on the refrigerator is 10J, the amount of heat absorbed from the reservoir at lower temperature is :

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99 J

100 J

90 J

1 J

answer is C.

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Detailed Solution

In heat engine, η=work doneQabsorbed ⇒110=10Qabs ⇒Qabs=100JNow, Qrej=Qabs−W=100=10=90J In refrigerator,Qabs=Qrej in heat engine∴Qabs=90J

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