Q.
A Carnot engine, having an efficiency of η=1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10J, the amount of energy absorbed from the reservoir at lower temperature is
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a
100 J
b
99 J
c
90 J
d
1 J
answer is C.
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Detailed Solution
The efficiency (η) of Carnot engine and the coefficient of performance(β) of a refrigerator are related as β=1−ηη Here, η=110 ∴β=1−110(110)=9. Also, Coefficient of performance(β) is given by β=Q2W, whereQ2 is the energy absorbed from the reservoir.Or, 9=Q210 ∴Q2=90J.
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