First slide

Refrigerator

Question

A Carnot engine, having an efficiency of η = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10J, the amount of energy absorbed from the reservoir at lower temperature is

Moderate

A

100 J
B

99 J
C

90 J
D

1 J

Solution

We know that coefficient of performance
$K = \frac{{{Q_2}}}{W}$
But $1 + K = \frac{1}{\eta };1 + K = \frac{1}{{\left( {\frac{1}{{10}}} \right)}} = 10$
$\therefore K = 9$
$K = 9 = \frac{{{Q_2}}}{W} \Rightarrow {Q_2} = 9W = 9 \times 10 = 90J$

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