Q.

A carnot engine having an efficiency of 110 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

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a

90 J

b

99 J

c

100 J

d

1 J

answer is A.

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Detailed Solution

The relation between coefficient of performance and efficiency of carnot engine is given asβ=1-ηη Given η=110,W=10 Jβ=1-110110=910·10=9 Since, β=Q2W, where Q2 is the amount of energy absorb from the reservor∴  Q2=βW=9×10=90 J
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