First slide

Heat engine

Question

A carnot engine operates between temperature limits of $127^{o} C and 27^{o} C$ . If the engine receives 2000 J of heat per cycle from the source, the amount of heat rejected per cycle to the sink is

Easy

A

1800 J
B

1200 J
C

1500 J
D

900 J

Solution

$\begin{array}{l} η = 1 - \frac{T_{2}}{T_{}} = \frac{Q_{1} - Q_{2}}{Q_{1}} \Rightarrow 1 - \frac{Q_{2}}{Q_{1}} = 1 - \frac{T_{2}}{T_{1}} \\ ∴ Q_{2} = Q_{1} (\frac{T_{2}}{T_{1}}) = 2000 \times (\frac{273 + 27}{273 + 127}) J = 1500 J \end{array}$

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