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Questions  

A Carnot engine operates with source at 1270C and sink at 270C. If the source supplies 40 kJ of heat energy, the work done by the engine is

a
30 kJ
b
4 kJ
c
10 kJ
d
1 kJ

detailed solution

Correct option is C

Efficiency of the Carnot cycle, η = 1-T2T1∴ η = 1-(273+27)(273+127) = 1-34 = 14Also η= Work done by engineHeat supplied by source = W∆Q = W40 kJW = 40 η = 40×14 = 10 kJ

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