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In a Carnot engine, when T₂ = 0⁰C and T₁ = + 200⁰C its efficiency is $η_{1}$ and when T₁ = 0⁰C and T₂ = 200⁰C, Its efficiency is $η_{2},$ then what is $η_{1} / η_{2}$

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0.577

0.733

0.638

Cannot be calculated

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detailed solution

Correct option is A

η=1−T2T1=T1−T2T1⇒η1=(473−273)473=200473 and η2=273−73273=200273So required ratio η1η2=273473=0.577

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In a Carnot engine, when T2 = 00C and T1 = + 2000C its efficiency is η1 and when T1 = 00C and T2 = 2000C, Its efficiency is η2, then what is η1/η2

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In a Carnot engine, when T₂ = 0⁰C and T₁ = + 200⁰C its efficiency is $η_{1}$ and when T₁ = 0⁰C and T₂ = 200⁰C, Its efficiency is $η_{2},$ then what is $η_{1} / η_{2}$