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Q.

A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500 K  it is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink)  temperature must be

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a

Efficiency of Carnot engine cannot be made larger than 50%

b

1200 K

c

750 K

d

600 K

answer is C.

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Detailed Solution

40100=500−TS500, TS=300 K 60100=T−300T⇒T=750 K
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