Q.

A Carnot engine whose low temperature reservoir is at 7oC has an efficiency of 50%. It is desired to increase the efficiency to 70%.. By how many degrees should the temperature of the high temperature reservoir be increased

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a

840 K

b

280 K

c

560 K

d

380 K

answer is D.

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Detailed Solution

Initially η = T1-T2T1  ⇒ 0.5 = T1-(273+7)T1⇒12 = T1-280T1  ⇒ T1 = 560 KFinalllyη1' = T1'-T2T1'  ⇒ 0.7 = T1'-(273+7)T1'⇒T1' = 933 K∴ Increase in temperature     = 933 - 560 = 373 K ≃ 380 K
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