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Q.

A carnot engine whose sink is at 300K has an efficiency of 40%. By how much should the temperature of the source be increased, so as to increase the efficiency by 50% of original efficiency?

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a

275 K

b

325 K

c

250 K

d

380 K

answer is C.

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Detailed Solution

1−300T1=0.4⇒T1=500KNow  1−300T11=1.5×0.4=0.6⇒T11=750K∴  T11−T1=250K
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