Questions
A carnot engine whose sink is at 300K has an efficiency of 40%. By how much should the temperature of the source be increased, so as to increase the efficiency by 50% of original efficiency?
detailed solution
Correct option is C
1−300T1=0.4⇒T1=500KNow 1−300T11=1.5×0.4=0.6⇒T11=750K∴ T11−T1=250KTalk to our academic expert!
Similar Questions
An ideal Carnot engine whose efficiency is 40% receives heat at 500K if the efficiency is to be 50%, the intake temperature for the same exhaust temperature is.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
