A Carnot engine whose sink is at a temperature of 300 K has an efficiency of 40%, By how much should the temperature of the source be increased so as to increase the efficiency to 60%

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

380 K

325 K

250 K

275 K

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

40100=1â300T1 or T1=500KFor 60% efficiency60100=1â300T1 or T1=750KSo the temperature should be increased by750 - 500 = 250 K

Watch 3-min video & get full concept clarity