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Q.

A Carnot engine whose sink is at a temperature of 300 K has an efficiency of 40%, By how much should the temperature of the source be increased so as to increase the efficiency to 60%

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a

380 K

b

325 K

c

250 K

d

275 K

answer is C.

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Detailed Solution

40100=1−300T1  or  T1=500KFor 60% efficiency60100=1−300T1  or  T1=750KSo the temperature should be increased by750 - 500 = 250 K
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