Q.
A Carnot engine working between 300 K and 600 K has work output of 800 J cycle-1. The amount of heat energy supplied from the source of engine in each cycle is
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a
800 J
b
1600 J
c
3200 J
d
6400 J
answer is B.
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Detailed Solution
The efficiency of Carnot engine is given byη=1−T2T1Given, T1=600K,T2=300K∴ η=1−300600⇒ η=1−12⇒η=12=50%Also, η=WQ⇒800Q=12Thus, amount of heat supplied from source to engine isQ=800×2=1600J
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