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Q.

A Carnot engine working between 300 K and 600 K has work output of 800 J cycle-1. The amount of heat energy supplied from the source of engine in each cycle is

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a

800 J

b

1600 J

c

3200 J

d

6400 J

answer is B.

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Detailed Solution

The efficiency of Carnot engine is given byη=1−T2T1Given,   T1=600K,T2=300K∴ η=1−300600⇒ η=1−12⇒η=12=50%Also,   η=WQ⇒800Q=12Thus, amount of heat supplied from source to engine isQ=800×2=1600J
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