First slide

Heat engine

Question

A Carnot engine working between 300 K and 600 K has a work output of 800 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is

Moderate

A

800 J
B

1600 J
C

3200 J
D

6400 J

Solution

$Î· = 1 â \frac{300}{600} = \frac{300}{600} = \frac{1}{2} Input = \frac{Output}{Î·} = 800 Ã 2 = 1600 J$

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