First slide

Heat engine

Question

A Carnot engine working between 300 K and 600 K has a work output of 800 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is

Easy

A

800 J
B

1600 J
C

3200 J
D

6400 J

Solution

$\begin{array}{l} η = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{Q_{2}}{Q_{1}} \\ ∴ \frac{T_{2}}{T_{1}} = \frac{Q_{2}}{Q_{1}} or Q_{1} = Q_{2} (T_{1} / T_{2}) \\ ∴ Q_{1} = 800 \times \frac{600}{300} = 1600 J \end{array}$

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