Questions
A Carnot's engine has an efficiency of 50% at sink temperature 500C. Calculate the temperature of source.
a
1330C
b
1430C
c
1000C
d
3730C
detailed solution
Correct option is D
Efficiency of Carnot's engine, η=1−T2T1 …(i)where, T2 is temperature of sink and T1 is the temperature of the source.Here, η=50%,T2=50∘C=50+273=323KPutting these values in Eq. (i), we get 50100=1−323T1⇒ T=646K=373∘CTalk to our academic expert!
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