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Q.

A Carnot's engine has an efficiency of 50% at sink temperature 500C. Calculate the temperature of source.

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a

1330C

b

1430C

c

1000C

d

3730C

answer is D.

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Detailed Solution

Efficiency of Carnot's engine,  η=1−T2T1   …(i)where, T2 is temperature of sink and T1 is the temperature of the source.Here,   η=50%,T2=50∘C=50+273=323KPutting these values in Eq. (i), we get 50100=1−323T1⇒ T=646K=373∘C
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