A Carnot's engine is made to work between 200oC and 0oC first and then between 0oC and -200oC. The ratio of efficiencies of the engine in the two cases is

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1.73:1

1:1.73

1:1

1:2

answer is B.

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Detailed Solution

In first case η1=1−T2T1=1−(273+0)(273+200)=200473 In second case η2=1−(273−200)(273+0)=200273⇒ η1η2=1473273=1:1.73

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