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Q.

A carnot’s engine operating between temperatures T1  and  T2 has efficiency 16 . When T2  is lowered by 62K , its efficiency increases to 13 . Then T1  and  T2 are respectively

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a

372 K and  310 K

b

372 K and 330 K

c

330 K and 268 K

d

310 K and 248 K

answer is A.

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Detailed Solution

case(i)   η=1−T2T1                                 16=1−T2T1−(1)                 case(ii)    η1=1−T21T1                                         η1=1−(T2−62)T1                                         =1−T2T1+62T1                                         η1=η+62T1                 By given date  η1=2n                                         2η=η+62T1                 n=62T1⇒T1=372k                 ⇒(1)⇒16=1−T2372                         T2=310k                 T1=372k&T2=310k.
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