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A Carnot’s engine, with its cold body at 170C has 50% efficiency. If the temperature of its hot body is now increased by1450C , the efficiency becomes

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Detailed Solution

η=1−T2T1=0.5∴T1=2T2=2(17+273)=580K=3070CNow the temperature of hot body is increased by 1450C∴T1'=3070+1450=4520C=725K    T2=17+273=290K∴η'=1−290725×100=60%
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