A Carnot’s engine works as a refrigerator between 250 K and 300 K. It receives 500 cal heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is :

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420 J

772 J

2100 J

2520 J

answer is A.

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Detailed Solution

β=T1T1-T2 Q2W=T2T1-T2 500×4.2W=250300-250 W=500×4.25=420J

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