A cavity of radius r is made inside a solid sphere. The volume charge density of the remaining sphere is ρ. The centre of sphere and centre of cavity are separated by a distance a. The magnitude of electric field inside the cavity is

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E=ρa3ε0

E=ρaε0

E=ρr3ε0

E=ρrε0

answer is A.

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Detailed Solution

E→1=ρr→3ε0E→2=−ρ(r→−a→)3ε0E→=E→1+E→2=ρr→3ε0+−ρ(r→−a→)3ε0=+ρa→3ε0= constant.

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