A cavity of radius r is made inside a solid sphere. The volume charge density of the remaining sphere is ρ. An electron (charge e, mass m) is released inside the cavity from point P as shown in figure. The center of sphere and center of cavity are separated by a distance a. The time after which the electron again touches the sphere is
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a
62 rε0mepa
b
2 rε0mepa
c
6 rε0mepa
d
rε0mepa
answer is A.
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Detailed Solution
Acceleration of electron A=eE/m (in backward direction). and E=ρa3ε0 or A=epa3ε0mDistance traveled by electron where it hits the wall of cavity is S=2r cosθ=r2Hence using S=12At2t=62 rε0meρa
A cavity of radius r is made inside a solid sphere. The volume charge density of the remaining sphere is ρ. An electron (charge e, mass m) is released inside the cavity from point P as shown in figure. The center of sphere and center of cavity are separated by a distance a. The time after which the electron again touches the sphere is