A CE amplifier is designed with a transistor having α=0.99. Input impedance 1kΩ and load 10kΩ. Voltage gain will be
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a
9900
b
99000
c
99
d
990
answer is D.
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Detailed Solution
α=0.99,Ri/p=1kΩ=1000Ω, Ro/p=10kΩ=10000Ω , Voltage gain = ?Volatage Gain = Vo/pVi/p,Voltage Gain = β×10=α1−α×10 (∴β=α1−α)=0.991−0.99×10=0.99×100.01=99×101=990