First slide

Transistors

Question

A CE amplifier is designed with a transistor having $α = 0.99$ . Input impedance $1 k Ω$ and load $10 k Ω$ . Voltage gain will be

Moderate

A

9900
B

99000
C

99
D

990

Solution

$\begin{matrix} α = 0.99, \\ R_{i / p} = 1 k Ω = 1000 Ω, \end{matrix}$
$R_{o / p} = 10 k Ω = 10000 Ω,$
$V o l t a g e g a i n = ?$
$V o l a t a g e G a i n = \frac{V_{o / p}}{V_{i / p}},$
$V o l t a g e G a i n = β \times 10 \begin{array}{l} = \frac{α}{1 - α} \times 10 (∴ β = \frac{α}{1 - α}) \end{array}$
$\begin{array}{l} = \frac{0.99}{1 - 0.99} \times 10 \\ = \frac{0.99 \times 10}{0.01} = \frac{99 \times 10}{1} = 990 \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App