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Q.

For a CE transistor amplifier, the audio signal voltage across the collector resistance of 2kΩ is 2V. Suppose the current amplification factor of the transistor is 100. The value of RB in series with  VBB supply of 2V, if the DC base current has to be10 times the signal current is

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a

4kΩ

b

14kΩ

c

28kΩ

d

54kΩ

answer is B.

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Detailed Solution

The output AC voltage is 2V. So the AC collector current ic=22000=1mAThe signal current through the base is therefore , given byiB=icβThe D.C base current has to be 10 x iB∴ RB=VBB−VBEIB,VBE=0.6V∴ RB=(2−0.6)0.10=14kΩ
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For a CE transistor amplifier, the audio signal voltage across the collector resistance of 2kΩ is 2V. Suppose the current amplification factor of the transistor is 100. The value of RB in series with  VBB supply of 2V, if the DC base current has to be10 times the signal current is