First slide

Projection Under uniform Acceleration

Question

The ceiling of a hall is 40 m high. Then the maximum possible range of a projectile thrown at 56 m/s without hitting the ceiling of the hall is (Take g = $9.8 m / s^{2}$ )

Moderate

Solution

$\begin{array}{l} \frac{{(56)}^{2} \sin^{2} α}{2 x 9 .8} = 40 \Rightarrow \sin α = \frac{1}{2} \Rightarrow α = 30^{o} \\ ∴ R_{\max} = \frac{56^{2}}{9 .8} \sin (2 {x 30)}^{o} m = 160 \sqrt{3} m . \end{array}$

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