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The ceiling of a hall is 40 m high. Then the maximum possible range of a projectile thrown at 56 m/s without hitting the ceiling of the hall is (Take g = 9.8 m/s2)

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Detailed Solution

(56)2sin2α2x9.8=40 ⇒ sin α=12 ⇒ α=30o∴ Rmax= 5629.8 sin ( 2 x 30)o m =1603 m.

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