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Projection Under uniform Acceleration

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Question

The ceiling of a hall is 40 m high. Then the maximum possible range of a projectile thrown at 56 m/s without hitting the ceiling of the hall is (Take g = 9.8 m/s2)

Moderate
Solution

(56)2sin2α2x9.8=40      sinα=12α=30o       Rmax=5629.8sin ( 2x30)om=1603m.


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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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