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Q.

A cell can be balanced against 110 cm and 100 cm of potentiometer wire respectively when in open circuit and when short circuited through a resistance of 10Ω . The internal resistance of the cell is

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a

0.9Ω

b

1.0Ω

c

1.5Ω

d

2.0Ω

answer is B.

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Detailed Solution

Balancing length l1=110 cm Balancing length l2=100 cm Resistance R=10 Ω Internal resistance r=? r=l1−l2l2R     = 110−100100×10 ∴  r=1 Ω
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