Questions
A cell of emf E has an internal resistance r and is connected to a rheostat. When resistance R of rheostat is changed, correct graph of potential difference across it is
detailed solution
Correct option is D
V=IR=ERR+r ⇒ V=E1+r/RSo as R increases, V also increases. Also at R = 0, V = 0. But maximum value of V can be E for R= ∞ so the graph can be as drawn below.Talk to our academic expert!
Similar Questions
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengths and radii of the wires are in the ratio of (4/3) and (2/3), then the ratio of the currents passing through the wires will be
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