Q.

A cell of emf E has an internal resistance r and is connected to a rheostat. When resistance R of rheostat is changed, correct graph of potential difference across it is

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a

b

c

d

answer is D.

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Detailed Solution

V=IR=ERR+r ⇒  V=E1+r/RSo as R increases, V also increases. Also at R = 0, V = 0. But maximum value of V can be E for R= ∞ so the graph can be as drawn below.
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