First slide

Diodes

Question

A cell of emf 4.5 V is connected to a junction diode whose barrier potential is 0.7 V. If the external resistance in the circuit is 190Ω, then the current in the circuit in Ampere

Easy

Solution

$P o t e n t i a l D r o p a c r o s s e x t e r n a l r e s i s t o r = V - V_{D} = 4.5 - 0.7 = 3.8 V$
$C u r r e n t i n t h e c i r c u i t = I = \frac{V - V_{D}}{R} = \frac{4.5 - 0.7}{190} = \frac{3.8}{190} = 0.02 A$

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