First slide

Diodes

Question

A cell of emf 5V is connected to a junction diode whose barrier potential is 0.3V. If the external resistance in the circuit is 200Ω, then the current in the circuit in Ampere

Easy

Solution

$P o t e n t i a l d r o p a c r o s s e x t e r n a l r e s i s \tan c e = V - V_{b} = 5 - 0.3 = 4.7 V$
$∴ C u r r e n t = I = \frac{V - V_{b}}{R} = \frac{5 - 0.3}{200} = \frac{4.7}{200} = 0.0235 A = 0.02 A$

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