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Q.

A cell of emf 5V is connected to a junction diode whose barrier potential is 0.3V. If the external resistance in the circuit is 200Ω, then the current in the circuit in Ampere

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answer is 0000.02A.

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Detailed Solution

Potential drop across external resistance =V−Vb = 5-0.3=4.7 V ∴Current= I=V−VbR=5−0.3200=4.7200=0.0235A                =0.02A
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A cell of emf 5V is connected to a junction diode whose barrier potential is 0.3V. If the external resistance in the circuit is 200Ω, then the current in the circuit in Ampere