The cell has an emf of 2 V and the internal resistance of  this cell is 0.1  Ω. It is connected to resistance of 3.9  Ω, the voltage across the cell will be

The voltage across cell terminal will be given byV=E−irwhere r is internal resistance.Also current, i=ER+r∴    V=E−ER+rrPutting the numerical values, we haveE=2V,  r=0.1  Ω,  R=3.9  ΩV=2−23.9+0.1  ×  0.1V = 1.95 V