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The cell has an emf of 2 V and the internal resistance of  this cell is 0.1  Ω. It is connected to resistance of 3.9  Ω, the voltage across the cell will be

a
1.5 V
b
2 V
c
1.95 V
d
1.8 V

detailed solution

Correct option is C

The voltage across cell terminal will be given byV=E−irwhere r is internal resistance.Also current, i=ER+r∴    V=E−ER+rrPutting the numerical values, we haveE=2V,  r=0.1  Ω,  R=3.9  ΩV=2−23.9+0.1  ×  0.1V = 1.95 V

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