48 cells each of internal resistance 1Ω are arranged in a mixed combination and the combination is connected across a resistor of resistance 3Ω. Number of cells in each row is n and number of rows is m if maximum current flows through the 3Ω resistor, then
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a
m=3,n=6
b
m=4,n=12
c
m=8,n=6
d
m=2,n=24
answer is B.
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Detailed Solution
mn=N ....(1) and for maximum current, mR=Nr ......(2)From (1) and (2), m=NrR=48×13=4 and n=484=12