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The centre of mass of a system of two particles of masses is at distance 8 cm from and at a distance 12 cm from . Then
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By Expert Faculty of Sri Chaitanya
a
m1m2=23
b
m1m2=14
c
m1m2=12
d
m1m2=32
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Correct option is D
Distance of centre of mass from C,rc=m2×12+m1×−8m1+m2Since C is the centre of mass, rc=0∴ 12m2−8m1=0⇒m1m2=128=32Similar Questions
Where will be the centre of mass on combining two masses m and M (M > m)
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