Certain amount of an ideal gas is contained in a closed vessel. The vessel is moving with a constant velocity v. The molecular mass of gas is M. The rise in temperature of the gas when the vessel is suddenly stopped is γ=CP/CV
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Mv2(γ−1)2R(γ+1)
b
Mv2(γ−1)2R
c
Mv22R(γ+1)
d
Mv22R(γ−1)
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
If m is the total mass of the gas, then its kinetic energy =1/2mv2 When the vessel is suddenly stopped, total kinetic energy will increase the temperature of the gas (because process will be adiabatic), i.e., 12mv2=μCvΔT=mMCvΔT⇒mMRγ−1ΔT=12mv2 As Cv=Rγ−1⇒ΔT=Mv2(γ−1)2R