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Q.

A certain balloon maintains an internal gas pressure of P0=100  kPa  until the volume reaches V0=20  m3 . Beyond a volume of 20  m3 , the internal pressure varies as P=P0+2k(V−V0)2  where P  is in kPa,  V  is in m3  and k  is a constant (k=1kPa/m3) . Initially the balloon contains helium gas at 200C , 100  kPa  with a 15m3  volume. The balloon is then heated until the volume becomes 25 m3  and the pressure is 150 kPa. Assume ideal gas behaviour for helium. The work done by the balloon for the entire process in kJ  is

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a

1256

b

1414

c

1083

d

1512

answer is C.

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Detailed Solution

Work done by the balloon W=∫15 m320 m3P0dV+∫20 m325 m3pdV  =∫15 m320 m3P0dV+∫20 m325 m3[P0+2(V−V0)2]dV                         =[100×5+100×5+2×(25−20)33]kJ=1083  kJ
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