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A certain body weighs 22.42 g and has a measured volume of 4.7cc. The possible error in the measurement of mass and volume are 0.01 g and 0.1 cc. Then maximum error in the density will be
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Correct option is B
Density ρ= mass m volume VTake logarithm to take base e on the both sides of eqn (i), we get lnρ = lnm – lnV .....(ii)Differentiate eqn (ii), on both sides, we get Δρρ=Δmm−ΔVVErrors are always added. Error in the density ρ will be =Δmm+ΔVV×100%=0.0122.42+0.14.7×100%=2%Talk to our academic expert!
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