Q.
In a certain circuit current changes with time according to i=2t. r.m.s. value of current betweent=2s to t=4s will be
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a
3A
b
33A
c
23A
d
(2−2)A
answer is C.
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Detailed Solution
i2¯=∫ i2dt∫ dt=∫24(4t)dt∫24dt=4∫24t dt2==2t2224=t224=12 ⇒irms=i2=12=23A
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