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Q.

In a certain circuit current changes with time according to  i=2t. r.m.s. value of current betweent=2s   to t=4s  will be

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a

3A

b

33A

c

23A

d

(2−2)A

answer is C.

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Detailed Solution

i2¯=∫  i2dt∫  dt=∫24(4t)dt∫24dt=4∫24t dt2==2t2224=t224=12 ⇒irms=i2=12=23A
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