At a certain depth of an incompressible liquid, the absolute pressure is p. At twice this depth, the absolute pressure is p1. Then
p1=2p
p1>2p
p1<2p
p1=2.5p
p=p0+pgh where p0=atmospheric pressure
p1=p0+p.g.2h
∴p1=p0+2(p−p0)=2p−p0<2p