Story
NEET AITS
Story
Mock Tests
Story
Live Class
Story
JEE AITS

Questions  

At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10 ms-1. The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms–2)

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
1s
b
2 s
c
1.5 s
d
1.75 s

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is A

As the fragments are identical , their velocities just after explostion are equal in magnitude but oppositely directed.Now = Since are mutually perpendicular
ctaimg

ctaimg

Similar Questions

A body of mass 1 kg is moving along positive x-axis with velocity 2 m/s. At t = 0, a constant force, parallel to positive y-axis, starts acting on the body and after 5 sec, speed of the body is found to be 4 m/s. Then work done by the force in 5 sec is

Want to Improve your productivity
talk to our academic experts now !!

counselling
india
+91

whats app icon