Questions
At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10 ms-1. The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms–2)
detailed solution
Correct option is A
As the fragments are identical , their velocities just after explostion are equal in magnitude but oppositely directed.Now = Since are mutually perpendicularTalk to our academic expert!
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A body of mass 1 kg is moving along positive x-axis with velocity 2 m/s. At t = 0, a constant force, parallel to positive y-axis, starts acting on the body and after 5 sec, speed of the body is found to be 4 m/s. Then work done by the force in 5 sec is
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