At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10 ms-1. The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms–2)
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a
1s
b
2 s
c
1.5 s
d
1.75 s
answer is A.
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Detailed Solution
As the fragments are identical , their velocities just after explostion are equal in magnitude but oppositely directed.Now = Since are mutually perpendicular