Q.

At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10 ms-1. The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms–2)

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a

1s

b

2 s

c

1.5 s

d

1.75 s

answer is A.

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Detailed Solution

As the fragments are identical , their velocities just after explostion are equal in magnitude but oppositely directed.Now = Since are mutually perpendicular
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At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10 ms-1. The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms–2)