Questions
In a certain machine at a fun fair, a man stands against the wall of a circular room of radius 3 m. The room rotates about a vertical axis through the centre of the floor at 2 rad/sec., then the floor is lowered- If the man does not slip vertically downwards, the least value of the coefficient of friction between the man and wall is
detailed solution
Correct option is A
When the machine rotates. the man also rotates with the wall. The contact force R between the wall and man is centripetal force. Due to this contact force R, there is frictional force µ R. The upward frictional force is balanced by weight of the man. HenceR=mv2r= mÏ2rand μR=mgμmÏ2r=mg or μ=gÏ2r.Talk to our academic expert!
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