First slide

Energy released in nuclear reactions -Q-value

Question

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)

Easy

A

6.675 MeV
B

13.35 MeV
C

2.67 MeV
D

26.7 MeV

Solution

$A s_{1}^{2} H +_{1}^{2} H \to_{2}^{4} H e H e r e, Δ M = 0.02866 u ∴ T h e e n e r g y l i b e r a t e d p e r u i s = \frac{Δ M \times 931}{4} M e V = \frac{0.02866 \times 931}{4} M e V = \frac{26.7}{4} M e V = 6.675 M e V$

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