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A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)

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By Expert Faculty of Sri Chaitanya
a
6.675 MeV
b
13.35 MeV
c
2.67 MeV
d
26.7 MeV

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detailed solution

Correct option is A

As 12H+12H→24He Here, ΔM=0.02866 u ∴ The energy liberated per u is =ΔM×9314MeV =0.02866×9314MeV=26.74MeV=6.675MeV
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Similar Questions

What is the total energy emitted for given fission reaction

 01n+92235U92236U4098Zr+52136Te+201n

The daughter nuclei are unstable therefore they decay into stable end products M 4298o and X 54136e by successive emission of β-particles. Let mass of   01n=1.0087 amu, mass of  92235U=236.0526 amu, mass of  54136Xe=135.9170 amu, mass of M 4298o = 97.9054 

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