First slide
Energy released in nuclear reactions -Q-value
Question

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)

Easy
Solution

As 12H+12H24He Here, ΔM=0.02866u  The energy liberated per u is =ΔM×9314MeV =0.02866×9314MeV=26.74MeV=6.675MeV

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