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A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)

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6.675 MeV

13.35 MeV

2.67 MeV

26.7 MeV

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detailed solution

Correct option is A

As 12H+12H→24He Here, ΔM=0.02866 u ∴ The energy liberated per u is =ΔM×9314MeV =0.02866×9314MeV=26.74MeV=6.675MeV

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What is the total energy emitted for given fission reaction

$_{0}^{1} n +_{92}^{235} U ⟶_{92}^{236} U ⟶_{40}^{98} Z r +_{52}^{136} T e + 2_{0}^{1} n$

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