A certain mass of you at 273 k is expanded to 256 times its volume under adiabatic temperature is
-235.65o C
-182o C
-204.75o C
Zero
For adiabatic process, TVγ−1= constant ⇒T2T1=V1V2γ−1⇒T2=V1V2γ−1×T1⇒T2=12561.2−1×273=1256023×273⇒T2=273×14=68.25K=−204.75∘C