Questions
A certain mass of you at 273 k is expanded to 256 times its volume under adiabatic temperature is
a
-235.65o C
b
-182o C
c
-204.75o C
d
Zero
detailed solution
Correct option is C
For adiabatic process, TVγ−1= constant ⇒T2T1=V1V2γ−1⇒T2=V1V2γ−1×T1⇒T2=12561.2−1×273=1256023×273⇒T2=273×14=68.25K=−204.75∘CTalk to our academic expert!
Similar Questions
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
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