A certain metallic surface is illuminated with monochromatic light of wavelength, λ. The stopping potential for photoelectric current for this light is 3V0. If the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength for this surface for photo-electric effect is
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a
π4
b
λ6
c
6λ
d
4λ
answer is D.
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Detailed Solution
According to Einstein's photoelectric equation eVs=hcλ-hcλ0 where Vs= Stopping potential λ= Incident wavelength λ0= Threshold wavelength or Vs=hce1λ-1λ0for the first case 3V0=hce1λ-1λ0for the second caseV0=hce12λ-1λ0Divide eqn. (i) by (ii), we get 3=1λ-1λ012λ-1λ0 312λ-1λ0=1λ-1λ0 32λ-3λ0=1λ-1λ0 12λ=2λ0 or λ0=4λ