First slide

Transistors

Question

A certain npn transistor has the common emitter output characteristics as shown in figure.
The emitter current at $V_{c c} = 10 V$ and $I_{b} = 60 μ A$ is $P \times 10^{- 4} A$ . Then the value of p is -------------------

Moderate

A

60.10
B

60.30
C

60.60
D

60.90

Solution

$A t V_{c c} = 10 V,$
$I_{c} = 6 m A = 6 \times 10^{- 3} A,$
$I_{b} = 60 μ A = 60 \times 10^{- 6} A = 0.060 \times 10^{- 3} A,$
$W e k n o w, I_{e} = I_{b} + I_{c}$
$I_{e} = 0.060 \times 10^{- 3} + 6 \times 10^{- 3} = 60.6 \times 10^{- 4} A$

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