A certain npn transistor has the common emitter output characteristics as shown in figure.The emitter current at Vcc=10V and Ib=60μA is P×10−4A . Then the value of p is -------------------
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a
60.10
b
60.30
c
60.60
d
60.90
answer is C.
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Detailed Solution
At Vcc=10V,Ic=6mA=6×10−3A ,Ib=60μA=60×10−6A=0.060×10−3A ,We know, Ie=Ib+IcIe=0.060×10−3+6×10−3=60.6×10−4A