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Q.

A certain number of spherical drops of a liquid of radius 'f coalesce to form a single drop of radius 'R' and volume 'V'. If  'T' is the surface tension of the liquid, then :

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a

energy =4VT1r-1Ris released.

b

energy =3VT1r-1Ris absorbed

c

energy =3VT1r-1Ris released

d

energy is neither released nor absorbed

answer is C.

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Detailed Solution

As surface area decreases so energy is released Released energy =4πR2T[n13-1]Where, R=n13r                =4πR3T1r-1R=3VT1r-1R
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