Certain perfect gas is found to obey PV32= constant during adiabatic process. If such a gas at initial temperature T is adiabatically compressed to half of the initial volume, its final temperature will be
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a
2 T
b
2T
c
22 T
d
4 T
answer is A.
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Detailed Solution
pv32=constant here γ=32 T1v1 γ−1=T2v2 γ−1 T1 Vγ−1=T2(V2)γ−1 T2=T×2γ−1 =T.232−1=2T